Respuesta :
Answer:
3120.75J
Explanation:
So, we have the formula [tex]q = mc\Delta t[/tex]. For this example, q is the heat energy in Joules, m is the mass in grams, c is the specific heat capacity in [tex]\frac{J}{{g\°C}}[/tex], and [tex]\Delta[/tex]t is the change in temperature. In this case, m = 47.5g, c = 0.9 [tex]\frac{J}{{g\°C}}[/tex], and [tex]\Delta[/tex]t = 94-21 = 73°C. Plugging in the values, we get the joules of heat required to raise 47.5g of Al from 21°C to 94°C which is stated above. You can double check my answer but that should be it. An important thing to be aware of are the units. Sometimes, the heat capacity may not be [tex]\frac{J}{{g\°C}}[/tex]. I may be in Kelvin or something. Anyways, hope this helps.
