I need help! Find the equation of a line parallel to 3x-3y=5 that contains the point (-1,-5). Write the equation in slope Intercept form.
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the equation of the line is y= x-4
Step-by-step explanation:
so so the first thing that you're going to do is get y alone
-x-5=y
next you're going to find your slope which in this case is negative one.
after that in order to find the equation of a parallel line you're going to find the reciprocal of the slope.
so in this case the reciprocal is one.
next you're going to substitute in the cordinates to find the y intercept
x+b=y. (-1)+b= -5. (. b is the y intercept)
b= -4