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Answer:

The sum of 3 consecutive integers is 13 more than twice the smallest integer. Find the integer.

x + (x+1) + (x+2) = 2x + 13

3x + 3 = 2x + 13:

3x - 2x = 13 - 3

x = 10 is the smallest integer:

Check: 10 + 11 + 12 = 2(10) + 13

The integers will be equal to 10, 11, and 12 respectively.

What is an expression?

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

The sum of 3 consecutive integers is 13 more than twice the smallest integer. The integer will be calculated as below:-

x + (x+1) + (x+2) = 2x + 13

3x + 3 = 2x + 13:

3x - 2x = 13 - 3

x = 10 is the smallest integer:

Check: 10 + 11 + 12 = 2(10) + 13 = 33

Therefore, the integers will be equal to 10, 11, and 12 respectively.

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