Respuesta :
Answer:
The radius, r ≈ 6.55 m
Step-by-step explanation:
The given parameters are;
An inscribed hexagon in a circle
The area of the hexagon = Area of the circle - 24 m²
The formula for the area of the circle = π·r² = π × r²
The area of each of the six equilateral triangle in the hexagon = √3/4 × r²
Where;
r = The radius of the circle
The area of a sector of a circle in which the equilateral triangle is inscribed = 60/360×π·r² = 1/6×π·r² = 1/6 × Area of the circle
Given that the sector of the circle in which one of the six equilateral triangles of the hexagon is inscribed is 1/6 the area of the circle, the difference in area between the equilateral triangle and the sector = 24/6 = 4
Therefore, the difference in the area between the sector of the circle and the area of the equilateral triangle = 4 m²
We then write; 1/6×π·r²- √3/4 × r² = 4
r²·(1/6×π- √3/4) = 4
r² = 4/(1/6 ×π - √3/4) = 48/(2·π -3·√3)
r = √(48/(2·π -3·√3) = 6.55 m to 2 decimal places
The radius, r ≈ 6.55 m.
