Kai took five tests this semester. His scores are listed below.

92, 88, 90, 96, 84

What is the mean absolute deviation of Kai's test scores?In decimals

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Answer:

3.2 0w0, hope this helps!

Step-by-step explanation:

I did this before

The mean absolute deviation of kai's test scores is 3.2.

What is mean absolute deviation?

The mean absolute deviation of a dataset is the average distance between each data point and the mean.

According to the given question

We have

the given data 92, 88, 90, 96, 84

For calculating mean absolute deviation

we will first calculate mean

mean = [tex]\frac{92+88+90+96+84}{5} =\frac{450}{5} = 90[/tex]

Now we will calculate the distance between each data point and the mean :

  • |92 -90| =2
  • |88-90|  =2
  • |90-90| =0
  • |96-90| = 6
  • |84 -90| = 6

Add the distances together

2+2+0+6+6 = 16

Divide the sum by number of data points.

MAD( mean absolute deviation ) = [tex]\frac{16}{5} =3.2[/tex]

Hence, the mean absolute deviation of Kai's test scores is 3.2.

Learn more about the mean absolute deviation here:

https://brainly.com/question/10528201?referrer=searchResults

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