Respuesta :

256708

Answer:

No real solutions

Step-by-step explanation:

You use the quadratic formula.

x = −b ± √(b^2 − 4ac)/2a where y = ax^2 + bx + c

b is 0, a is 1, and c is 4.

-0 ± √(0^2 − 4 x 1 x 4)/ 2(1)

±√(-16)/2

Split √(-16) into √(16) and √(-1).

Now, i = √-1

So you get ±√(-16) = ±4i.

The original equation was ±√(-16)/2.

±4i / 2 = ±2i

The answer is x = ±2i

(Note: ± means positive or negative)