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An Alaskan rescue plane traveling 46 m/s drops a package of emergency rations from a height of 101 m to a stranded party of explorers. The acceleration of gravity is 9.8 m/s^2. Where does the package strike the ground relative to the point directly below where it was released? Answer in units of m.

Respuesta :

Answer:

The package strikes 207 m at the ground relative to the point.

Explanation:

Given that,

Speed = 46 m/s

Height = 101 m

Acceleration = 9.8 m/s²

We need to calculate the time

Using equation of motion

[tex]s=ut+\dfrac{1}{2}gt^2[/tex]

Put the value in the equation

[tex]101=0+\dfrac{1}{2}\times9.8\times t^2[/tex]

[tex]t=\sqrt{\dfrac{2\times101}{9.8}}[/tex]

[tex]t=4.5\ sec[/tex]

We need to calculate the distance where the package strikes

Using formula of distance

[tex]x=vt[/tex]

Put the value into the formula

[tex]x=46\times4.5[/tex]

[tex]x=207\ m[/tex]

Hence, The package strikes 207 m at the ground relative to the point.

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