Answer:
The height to which the ball flies is 86.6 m.
Explanation:
Given that,
Time = 2.05 sec
Acceleration = 9.8 m/s²
We need to calculate the initial velocity of volleyball
Using equation of motion
[tex]v=u-at[/tex]
Where, u = initial velocity
a = acceleration
t = time
Put the value into the formula
[tex]0=u-9.8\times(2.05)^2[/tex]
[tex]u=41.2\ m/s[/tex]
We need to calculate the height of the the ball
Using equation of motion
[tex]v^2=u^2-2ah[/tex]
Put the value into the formula
[tex]0=(41.2)^2-2\times9.8\times h[/tex]
[tex]h=\dfrac{(41.2)^2}{2\times9.8}[/tex]
[tex]h=86.6\ m[/tex]
Hence, The height to which the ball flies is 86.6 m.
