Answer:
The values are [tex]x = 46 miles /hr [/tex]
[tex]y = 4 \ miles / hr[/tex]
Step-by-step explanation:
From the question we are told that
The distance covered is d = 264 miles
The time taken is [tex]t_1 = 6 hours[/tex]
The time taken for the return trip is [tex]t_2 = 5.5 \ hours[/tex]
Generally during the trip toward fishing spot , the velocity is mathematically represented as
[tex]v_t = \frac{d}{t_1 } = x - y[/tex]
=> [tex]v_t = \frac{264}{6 } = x - y[/tex]
=> [tex]x - y = 44 \cdots 1 [/tex]
Generally during the return trip , the velocity is mathematically represented as
[tex]v_r = \frac{d}{t_2} = x+ y[/tex]
=> [tex]v_r = \frac{264}{5.5} = x+ y[/tex]
=> [tex]48 = x+ y\cdots 2[/tex]
add equation 1 and 2
[tex]2x = 92[/tex]
=> [tex]x = 46 miles /hr [/tex]
substituting this into equation 1
[tex] 46 - y = 44 \cdots 1 [/tex]
=> [tex]y = 4 \ miles / hr[/tex]
