The complete question with the scale is missing, so i have attached it.
Answer:
930 g
Explanation:
The block surface is frictionless, therefore, the only force that can possibly be applied to the block from the hamster will be the normal force.
Now, the force of gravity on the hamster acts downward and equals mg. Hence, The normal component will be;
F_n = mgcosθ.
Now, if we Assume that the scale does not respond to horizontal force component, the downward component of the normal force will be expressed as;
F_d = F_n(cosθ)
The scale measures the downward component.
Earlier, we saw that; F_n = mgcosθ
Thus; F_d = mgcosθ × cosθ
F_d = mg(cos²θ)
Now, when the friction was high, the measurement of the scale was;
(m+ M)g
Where ;
m = mass of hamster
M = mass of block
Therefore, when the friction is removed the scale measurement is;
mgcos²θ + Mg or (mcos²θ + M)g
But this is in units of Newton's.
Thus;
Measurement in kg is;
(mcos²θ + M)
We are given;
m = 170 g = 0.17 kg
M = 830 g = 0.83 kg
From the attached scale image,
θ = 40°
Thus;
Measurement = (mcos²θ + M) = ((0.17 cos²40) + 0.83) = 0.93 kg or 930g
