volume of ozone : 19.15 ml
Further explanation
Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or
[tex]\tt \dfrac{r_{CO_2}}{r_{O_3}}=\dfrac{\sqrt{M_{O_3}} }{\sqrt{M_{CO_2}}} }[/tex]
rate of CO₂ , M CO₂ = 44,01 g/mol
[tex]\tt r~CO_2=\dfrac{20~ml}{100~s}[/tex]
- rate of O₃, M O₃ = 48 g/mol
[tex]\tt r~O_3=\dfrac{x}{100~s}[/tex]
volume of ozone
[tex]\tt \dfrac{r~{CO_2}}{r~O_3}=\dfrac{\sqrt{48} }{\sqrt{44.01} }\\\\\dfrac{20}{x}=\dfrac{\sqrt{48} }{\sqrt{44.01} }\\\\x=\dfrac{20.\sqrt{44.01} }{\sqrt{48} }=19.15~ml[/tex]
