Bags of flour at a local grocery store have a mean weight of 83 ounces with a standard deviation of 2 ounces. Which weight represents the 65th percentile?
A.82.2 ounces
B.82.5 ounces
C.83.5 ounces
D.83.8 ounces

Question

13-10-2020
Mathematics

contestada

Bags of flour at a local grocery store have a mean weight of 83 ounces with a standard deviation of 2 ounces. Which weight represents the 65th percentile?
A.82.2 ounces
B.82.5 ounces
C.83.5 ounces
D.83.8 ounces

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adefunkeadewole adefunkeadewole · Answer 1 · 2020-10-20T02:22:51+02:00

Answer:

D.83.8 ounces

Step-by-step explanation:

The z score for 65th percentile = 0.385

Mean weight of 83 ounces with a standard deviation of 2 ounces

The formula for calculating a z-score is z = (x-μ)/σ

where x is the raw score

μ is the population mean

σ is the population standard deviation

x = ??

Hence:

0.385 = (x - 83)/2

Cross Multiply

0.385 × 2 = x - 83

0.77 = x - 83

x = 83 + 0.77

x = 83.77 ounces

Approximately = 83.8 ounces

LegacyMClassOf2021 LegacyMClassOf2021 · Answer 2 · 2021-01-22T17:45:36+01:00

LegacyMClassOf2021 LegacyMClassOf2021

22-01-2021

Answer:

D.83.8 ounces

Step-by-step explanation:

The z score for 65th percentile = 0.385

Mean weight of 83 ounces with a standard deviation of 2 ounces

The formula for calculating a z-score is z = (x-μ)/σ

where x is the raw score

μ is the population mean

σ is the population standard deviation

x = ??

Hence:

0.385 = (x - 83)/2

Cross Multiply

0.385 × 2 = x - 83

0.77 = x - 83

x = 83 + 0.77

x = 83.77 ounces

Approximately = 83.8 ounces

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Bags of flour at a local grocery store have a mean weight of 83 ounces with a standard deviation of 2 ounces. Which weight represents the 65th percentile? A.82.2 ounces B.82.5 ounces C.83.5 ounces D.83.8 ounces

Respuesta :

Otras preguntas

Bags of flour at a local grocery store have a mean weight of 83 ounces with a standard deviation of 2 ounces. Which weight represents the 65th percentile?
A.82.2 ounces
B.82.5 ounces
C.83.5 ounces
D.83.8 ounces