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To celebrate a victory, a pitcher throws her glove straight up into the air with an initial velocity of 6.0 m/s. What is the maximum height of the glove? (Show work)

Respuesta :

Answer:

h = 1.8 m

Explanation:

The initial velocity of the glove, u =- 6 m/s

We need to find the maximum height of the glove. Let it is equal to h. Using equation of kinematics. At the maximum height v = 0

[tex]v^2-u^2=2ah[/tex], h is the maximum height and a = -g

[tex]0^2-(6)^2=2\times (-10)\times h\\\\h=\dfrac{36}{20}\\\\h=1.8\ m[/tex]

Hence, it will go up to a height of 1.8 m.