Answer:
[tex]n_O=6.00molO[/tex]
Explanation:
Hello.
In this case, since the molecular formula of barium sulfate is:
[tex]BaSO_4[/tex]
Which has four oxygen atoms, we can also say that one mole of barium sulfate has four moles of oxygen; in such a way, the moles of oxygen atoms in 1.50 moles of barium sulfate are:
[tex]n_O=1.50molBaSO_4*\frac{4molO}{1molBaSO_4} \\\\n_O=6.00molO[/tex]
Best regards.
