Answer:
[tex]n_{solute}=0.235mol[/tex]
Explanation:
Hello.
In this case, we are talking about molarity which is an unit of concentration relating the moles of the solute and the volume of the solution in liters only:
[tex]M=\frac{n_{solute}}{V_{solution}}[/tex]
Since the solute is the (NH4)2Fe(SO4)2 and the volume in liters:
[tex]V=94.00mL*\frac{1L}{1000mL} =0.094L[/tex]
Thus, for the given 2.50-M solution, the moles of solute result:
[tex]n_{solute}=M*V=2.50mol/L*0.094L\\\\n_{solute}=0.235mol[/tex]
Best regards.
