Answer:
[tex]\huge\boxed{y>4\ \vee\ y<-8}\\\boxed{y\in(-\infty;\ -8)\ \cup\ (4;\ \infty)}[/tex]
Step-by-step explanation:
[tex]|y+2|>6\iff y+2>6\ \vee\ y+2<-6\qquad|\text{subtract 2 from both sides}\\\\y+2-2>6-2\ \vee\ y+2-2<-6-2\\\\y>4\ \vee\ y<-8\Rightarrow y\in(-\infty;\ -8)\ \cup\ (4;\ \infty)[/tex]
