Hana rents a car for a day. Her car rental company charges $50 per day and $0.40 per mile. Peter rents a car from a different company that charges $70 per day and $0.30 per mile. How many miles do they have to drive before Hana and Peter pay the same price for the rental for the same number of miles?

Respuesta :

50 + .4x = 70 + .3x

.4x = .3x + 20

.1x = 20

x = 200

Let x be the number of miles.

They have to drive 200 miles.

They will drive 200 miles before paying same amount.

Let the number of miles that they will drive together and pay the same amount be represented by x.

Since Hana's car rental company charges $50 per day and then $0.40 per mile, this can be represented as:

= 50 + (0.40 × x)

= 50 + 0.40x

Since Peter rents a car from a different company that charges $70 per day and then $0.30 per mile, this will be:

= 70 + (0.30 × x)

= 70 + 0.30x

Then we will equate both Hana's and Peter's equation together and this will be:

50 + 0.40x = 70 + 0.30x

Collect like terms

0.40x - 0.30x = 70 - 50

0.1x = 20

x = 20/0.1

x = 200

In conclusion, they will drive 200 miles before paying thesame amount

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