Answer:
Explanation:
Q:
If 98 out of 200 individuals in a population express the recessive phenotype, what percent of the population would be heterozygotes?
A:
0.42 or 42%
The recessive phenotype is the phenotype that is expressed only when the recessive condition is found in both alleles.
The percent of the population that would be heterozygous is 42%
If 98 out of 200 individual express the recessive allele = 98/200 = 0.49. This is the phenotypic frequency of the recessive allele (q²)... q = 0.7 (√0.49)
Since p + q = 1
1 - 0.7 = 0.3 = p
To find the percent of heterozygous...p² + 2pq + q² = 1
Where 2 x 0.3x0.7= 0.42
Therefore, the percent of the population that are heterozygous is 42%
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