. Satisfied with the jeweler’s method, the customer next takes out a large and rigid bracelet, adds it to the measuring container and records the new mass and the volume level of the liquid, planning to use the same method to determine what it is made of. Unfortunately, the customer failed to notice that the bracelet was much larger than the ring, and was not fully submerged, but was partially protruding above the surface of the water. Do you believe that the density the customer calculated was higher or lower than the actual density of the bracelet? Explain how you came to your conclusion.

A widely used method to determine the density of a body is to measure its mass and measure its volume by immersing it in a transparent liquid, to measure its volume by the difference in volumes of the liquid then use the relationship

ρ = m / V

In this case, part of the body remains the force of the liquid, in this case using Archimedes' principle that establishes that the weight of the desalted liquid is equal to the thrust, let's use the equilibrium equation

B - W = 0

B = W

ρ_liquid g V_submerged = ρ_body g V_body

V_submerged = (ρ_body /ρ-liquid) V_body

We can see that the volume is only a fraction of the volume of the body, therefore when performing the division a higher value is obtained than the real one.