Given that,
The diameter of a tennis ball, d = 2.7 inches
Radius, r = 1.35 inches
The dimensions of the storage shed is 14 feet wide, 15 feet long, and 10 feet high.
Volume of the shed is, V = lbh
[tex]V=14\times 15\times 10\\\\V=2100\ \text{feet}^3[/tex]
We can convert radius from inches to feet :
1 foot = 12 inches
Radius, r = 0.1125 feet
Let there are x number of tennis balls that can fit in the shed. So,
[tex]x\times V_b=V_s\\\\\text{Where}\ V_b\ \text{and}\ V_s\ \text{volume of ball and shed}\\\\x=\dfrac{V_s}{\dfrac{4}{3}\pi r^3}\\\\x=\dfrac{2100}{\dfrac{4}{3}\pi \times (0.1125)^3}[/tex]
x = 352105.75 balls
or
x = 352106 balls
Hence, 352106 balls can fit in the storage shed.
