Answer:
[tex]y=6(x-8)-2\qquad\text{point-slope form}[/tex]
[tex]y=6x-50\qquad\text{slope-intercept form}[/tex]
Step-by-step explanation:
The equation of a line can be written in several forms. Two of the most-used forms are the point-slope and the slope-intercept forms.
The point-slope form requires to have one point (xo, yo) through which the line passes and the slope m. The equation expressed in this form is:
[tex]y=m(x-xo)+yo[/tex]
The slope-intercept form requires to have the slope m and the y-intercept b, or the y-coordinate of the point where the line crosses the y-axis. The equation is:
[tex]y=mx+b[/tex]
The line considered in the question has a slope m=6 and passes through the point (8,-2). These data is enough to find the point-slope form of the line:
[tex]\boxed{y=6(x-8)-2\qquad\text{point-slope form}}[/tex]
To find the slope-intercept form, we operate the above equation:
[tex]y=6x-48-2[/tex]
[tex]\boxed{y=6x-50\qquad\text{slope-intercept form}}[/tex]
