Answer:
Step-by-step explanation:
From the question we are told that
The sample size is n = 15
The level of significance is [tex]\alpha = 0.05[/tex]
The null hypothesis is [tex]H_o:\mu_1 = \mu_2 = \mu_3[/tex]
The alternative hypothesis is [tex]H_a : \mu_1 \ne \mu_2 \ne \mu_3[/tex]
Generally the degree of freedom is mathematically represented as
[tex]df = 5 + 5 + 5 - 3[/tex]
=> [tex]df = 12[/tex]
Generally the critical value of [tex]\alpha = 0.05[/tex] at a degree of freedom of [tex]df = 12[/tex] is
[tex]t_{0.05 , 12} = \pm 2.1788[/tex]
