contestada

During his recent skydiving adventure, Luke Skyfaller has reached a terminal speed of 9.8 m/s as he approach the ground with his parachute. During an attempt to snap one last photo with his camera Luke fumbled it from a height of 52.8 m above the ground determine the speed with which the camera hits the ground.

Respuesta :

Answer:

The correct solution is "33.62 m/s".

Explanation:

The given values are:

Speed

u = 9.8 m/s

Height

s = 52.8 m

As we know,

⇒ [tex]v^2 = u^2 + 2as[/tex]

On putting the estimated values, we get

⇒      [tex]=(9.8)^2+2\times 9.8\times 52.8[/tex]

⇒      [tex]=96.04+1034.88[/tex]    

⇒      [tex]=\sqrt{1130.92}[/tex]

⇒      [tex]=33.62 \ m/s[/tex]