Contrary to popular belief, a ski jumper does not achieve a large amount of "air" when doing a jump (less than 6 feet). This is because the ramp is almost horizontal while the landing is a steep hill. If a ski jumper leaves the hill at 26 m/s in the horizontal direction then travels 240 meters down the slope, what was the vertical distance (dy) that the ski jumper fell?

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onyebuchinnaji onyebuchinnaji · Answer 1 · 2020-10-14T03:30:51+02:00

Answer:

The vertical distance that the ski jumper fell is 417.45 m.

Explanation:

Given;

initial horizontal velocity of the jumper, [tex]V_x[/tex] = 26 m/s

horizontal distance of the jumper, dx = 240 m

The time of the motion is given by;

dx = Vₓt

t = dx / Vₓ

t = 240 / 26

t = 9.23 s

The vertical distance traveled by the diver is given by;

[tex]d_y = V_yt + \frac{1}{2}gt^2[/tex]

initial vertical velocity, [tex]V_y[/tex], = 0

[tex]d_y = \frac{1}{2}gt^2\\\\d_y = \frac{1}{2}(9.8)(9.23)^2\\\\d_y = 417.45 \ m[/tex]

Therefore, the vertical distance that the ski jumper fell is 417.45 m.