1. A dog of mass 5 kg jumps on a table of mass 30 kg. As the dog walks around on the table, what is the average force that the table applies to the dog?

The table is managing to keep the dog up, the dog is not moving up or down so the force that the table applies to the dog must be equal to the dogs weight - I draw this conclusion from Newton's 3rd law.

W= mg

W = 5 × 9.8

W = 49N

round to.one significant figure = 50N

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boffeemadrid boffeemadrid · Answer 2 · 2022-01-27T12:38:13+01:00

boffeemadrid boffeemadrid

27-01-2022

The force that the table applies on the dog is required.

The force that the table applies to the dog is [tex]10\ \text{N}[/tex]

m = Mass of dog = 5 kg

g = Acceleration due to gravity is assumed to be [tex]10\ \text{m/s}^2[/tex]

Force is given by

[tex]F=mg[/tex]

[tex]\Rightarrow F=5\times 10[/tex]

[tex]\Rightarrow F=10\ \text{N}[/tex]

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1. A dog of mass 5 kg jumps on a table of mass 30 kg. As the dog walks around on the table, what is the average force that the table applies to the dog? ​

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1. A dog of mass 5 kg jumps on a table of mass 30 kg. As the dog walks around on the table, what is the average force that the table applies to the dog?