Answer:
We have the function f(x) = 2x + 3
the processes which take place in this function are
we take x [x]
we multiply it by 2 [2x]
we add 3 to it [2x + 3]
To get the inverse of this function, we will do exactly the opposite of it
we will take the output of the initial function [y]
we will subtract 3 from it [y-3]
we will divide it by 2 [(y-3)/2]
We get the function:
[tex]f^{-1}[/tex](y) = (y-3) / 2
Inverse functions are used to get the initial value used in the function bu using the output of the function
[tex]f^{-1}[/tex](0) = (0-3)/2
[tex]f^{-1}[/tex](0) = -3/2
Therefore, the input of the function is -3/2 when the output is 0
