Answer:
The percentage of all animals at fair Y that are goats is greater than the percentage of all animals at fair X that are goats.
Step-by-step explanation:
From the bar chart, we can see that 100 goats were present at fair X and Y
Let us now calculate the percentage of goats at each fair:
Fair X = 100/645 * 100 = 15.5%
Fair Y =100/590 *100 = 16.9 %
Hence there was a greater percentage of goats at fair Y than at fair X.
The bar chart is missing and so i have attached it.
Also, the question is incomplete and the missing part of the question is;
Which of the following statements is supported by the bar chart?
a) The total number of cows, pigs, and horses combined is less at fair X than at fair Y.
b) Fair X has at least 20 more chickens than fair Y.
c) At fair X, the number of sheep is twice the number of horses.
d) The percentage of all animals at fair Y that are goats is equal to the percentage of all animals at fair X that are goats.
e) The percentage of all animals at fair Y that are goats is greater than the percentage of all animals at fair X that are goats.
The only Statement that supports the bar chart is statement E.
At fair X: Cows = 50, Pigs =60, Horses = 80. Total = 50 + 60 + 80 = 190
At fair Y: Cows = 60, Pigs = 80, Horses = 40. Total = 60 + 80 + 40 = 180
Total in fair X is greater than total in fair Y. Therefore statement in question is false.
At fair X; chickens = 90
At fair Y; chickens = 80
Difference = 90 - 80 = 10
Thus,statement in question is wrong.
Sheeps = 140
Horses = 80
Twice number of horses is not same as sheep. Thus, statement in question is wrong.
Percentage that are goats = 100/590 × 100 = 16.95%
Total number of animals at fair X = 50 + 60 + 80 + 90 + 100 + 125 + 140 = 645
Percentage that are goats = 100/645 × 100 = 15.5%
The percentages are not equal and so the statement in the question is wrong.
