Answer:
y = - [tex]\frac{2}{3}[/tex] x + 8
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
2x + 3y = 24 ( subtract 2x from both sides )
3y = - 2x + 24 ( divide all terms by 3 )
y = - [tex]\frac{2}{3}[/tex] x + 8 ← in slope- intercept form
The equation 2x+3y=24 in the slope-intercept form can be written as [tex]y = -\frac{2}{3}x+8[/tex]
From the question,
We are to write the given equation in the slope-intercept form
The slope-intercept form of an equation of straight line is written as
y = mx +c
To write the equation, 2x+3y=24, in the slope-intercept form, we will make y the subject of the equation
[tex]2x+3y=24[/tex]
First, subtract 2x from both sides of the equation
That is,
[tex]2x -2x +3y = 24 -2x[/tex]
This becomes
[tex]3y = 24 -2x[/tex]
Now, divide both sides by 3
[tex]\frac{3y}{3} =\frac{24-2x}{3}[/tex]
∴ [tex]y = \frac{24}{3}-\frac{2x}{3}[/tex]
[tex]y = 8-\frac{2}{3}x[/tex]
In the slope-intercept form, we get
[tex]y = -\frac{2}{3}x+8[/tex]
Hence, the equation 2x+3y=24 in the slope-intercept form can be written as [tex]y = -\frac{2}{3}x+8[/tex]
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