Plz HELP
Item 9
A conjecture and the paragraph proof used to prove the conjecture are shown.

Given: ABCD is a parallelogram. Segment DC bisects angle B D E. Prove: angle 1 is congruent to angle 3. Parallelogram A B C D. Two rays D B and D E share endpoints at vertex D. Ray D B extends diagonally up to the right from D C at vertex D forming interior angles A B D and B D C. Angle A B D is labeled 1 and angle B D C is labeled 2. Ray D E extends diagonally down to the right from segment D C at vertex D forming an exterior angle C D E. Angle C D E is labeled 3.

Drag an expression or phrase to each box to complete the proof.

It is given that ABCD is a parallelogram, so AB¯¯¯¯¯∥DC¯¯¯¯¯ by the definition of parallelogram. So, ∠1≅ ​∠2​ by the alternate interior angles theorem. It is also given that DC¯¯¯¯¯ bisects ∠BDE, so ∠2≅ Response area by the Response area. Therefore, Response area ≅∠3 by the Response area.

option choices
Transitive property of congruence
definition of angle bisector
∠1
∠2
∠3