Answer:
This expression reminds me a lot of Fermat's last theorem x^n+y^n=z^n where n is three(odd). Which is one of many famous diophantine equations such as the well known pythagorean theorem a^2+b^2 = c^2. Where one of the variables should be even, and all are coprime. The parity is odd since it has a remainder and is not evenly divisible. It has been proven that Fermat's last theorem does not have any real solutions because you would need a complex number to cancel out the cubes. You will also see that x^n+y^n=z^n does not have any solutions if n>=3. This cannot be factored either since the numbers are rational.
