Answer:
b. False
Step-by-step explanation:
The answer is false because the standard deviation was miscalculated.
We can compute the formula for calculating the standard deviation as:
[tex]\sigma = \sqrt{\dfrac{\sum (x_i-\overline x)^2}{n}}[/tex]
As a result of the square in the numerator of the summation, the square [tex]\sum (x_i-\overline x)^2[/tex] is usually non-negative.
Even if the data is positive, negative or zero, as a result of the above claim, the standard deviation is always non-negative.
Thus, the fact that the first student who finishes the calculation first and claim that the standard deviation is -1.8 is false.
