Answer:
The cross-sectional area is [tex]A = 7.59 *10^{-11} \ m^2[/tex]
Explanation:
From the question we are told that
The dimension of the cell is 6.9 × 10-4 cm by 1.1 × 10-3 cm = [tex]6.9*10^{-6} \ m \ by\ 1.1*10^{-5} \ m[/tex]
Generally the cross-sectional area is mathematically represented as
[tex]A = 6.9*10^{-6} * 1.1*10^{-5}[/tex]
=> [tex]A = 7.59 *10^{-11} \ m^2[/tex]
