Answer:
The correct relationships are T-fg=ma and L-fg=0.
(A) and (C) is correct option.
Explanation:
Given that,
Weight Fg = mg
Acceleration = a
Tension = T
Drag force = Fa
Vertical force = L
We need to find the correct relationships
Using balance equation
In horizontally,
The acceleration is a
[tex]T-Fd=ma[/tex]...(I)
In vertically,
No acceleration
[tex]w=L[/tex]
[tex]mg-L=0[/tex]
Put the value of mg
[tex]L-fg=0[/tex]....(II)
Hence, The correct relationships are T-fg=ma and L-fg=0.
(A) and (C) is correct option.
In the attached picture we can see the original question.
A water-skier with weight Fg = mg moves to the right with acceleration a. A horizontal tension force T is exerted on the skier by the rope, and a horizontal drag force Fd is exerted by the water on the ski. The water also exerts a vertical lift force L on the skier. The correct relationships are:
(A) [tex]T - F_d = ma[/tex]
(C) [tex]L - F_g = 0[/tex]
A water skier is moving to the right with acceleration a. If we analyze the forces in the horizontal direction, we can identify the tensión force (T), in the direction of the movement and the drag force (Fd), opposing to the movement. According to Newton's second law of motion, the resultant of these forces is equal to the product of the mass of the water skier and its acceleration.
[tex]T - F_d = ma[/tex]
In the vertical direction, we have the weight of the water skier (Fg) and the lift force (L) exerted on the skier by the water. The resultant of these 2 forces is zero, since there is no acceleration in the vertical direction.
[tex]L - F_g = 0[/tex]
A water-skier with weight Fg = mg moves to the right with acceleration a. A horizontal tension force T is exerted on the skier by the rope, and a horizontal drag force Fd is exerted by the water on the ski. The water also exerts a vertical lift force L on the skier. The correct relationships are:
(A) [tex]T - F_d = ma[/tex]
(C) [tex]L - F_g = 0[/tex]
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