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A seat on a Ferris wheel is level with the center of the wheel. The diameter of the wheel is 200 feet. Suppose the
wheel rotates 60°, causing the height of the seat to decrease. How much closer to the ground is the seat after the
rotation?
O 50 feet
O 50 feet
O 100 feet
O 100v3 feet
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A seat on a Ferris wheel is level with the center of the wheel The diameter of the wheel is 200 feet Suppose the wheel rotates 60 causing the height of the seat class=

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I think the answer is 50 but don’t listen to me

The required height of the seat from the ground is 100√3. Option D is correct.

A seat on a Ferris wheel is level with the center of the wheel. The diameter of the wheel is 200 feet. Suppose the wheel rotates 60°, causing the height of the seat to decrease. How much closer to the ground is the seat after the is to be determined.


What are trigonometric equations?

These are the equation that contains trigonometric operators such as sin, cos.. etc.. In algebraic operation.

Diameter = 200
Radius = Diameter/2 = 100
Rotational angle = 60°
Let the height be h
tan60 = h/100
√3 = h/100
100√3 = h

Thus, the required height of the seat from the ground is 100√3. Option D is correct.

Learn more about trigonometry equations here:

brainly.com/question/22624805

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