Respuesta :
Answer:
(A). The horizontal initial velocity is 25 m/s.
(B). The vertical initial velocity is 43.3 m/s.
(C). The velocity component is
[tex]u_{x}=u\cos\theta[/tex]
[tex]u_{y}=u\sin\theta[/tex]
Explanation:
Given that,
Initial velocity = 50.0 m/s
Angle = 60°
We need to calculate the component of velocity
Using formula of component
(A). Horizontal initial velocity
[tex]\cos\theta=\dfrac{u_{x}}{u}[/tex]
Put the value in to the formula
[tex]\cos60=\dfrac{u_{x}}{50}[/tex]
[tex]u_{x}=50\times\cos60[/tex]
[tex]u_{x}=25\ m/s[/tex]
(B). Vertical initial velocity
[tex]\sin\theta=\dfrac{u_{y}}{u}[/tex]
Put the value in to the formula
[tex]\sin60=\dfrac{u_{y}}{50}[/tex]
[tex]u_{y}=50\times\sin60[/tex]
[tex]u_{y}=43.3\ m/s[/tex]
The velocity component is
[tex]u_{x}=u\cos\theta[/tex]
[tex]u_{y}=u\sin\theta[/tex]
Hence, (A). The horizontal initial velocity is 25 m/s.
(B). The vertical initial velocity is 43.3 m/s.
(C). The velocity component is
[tex]u_{x}=u\cos\theta[/tex]
[tex]u_{y}=u\sin\theta[/tex]
