Answer:
[tex]a=0.8\ m/s^2[/tex]
Explanation:
Given that,
Mass of a toy, m = 0.62 kg
Horizontal force, F = 16.3 N
Force on the opposite direction, F' = 15.8 N
We need to find the acceleration of the toy.
Here, two forces are acting in opposite direction, the net force will be the difference of forces.
Net force = 16.3 N-15.8 N
=0.5 N
The formula for net force is given by :
F = ma
a is the acceleration of the toy
[tex]a=\dfrac{F}{m}\\\\a=\dfrac{0.5\ N}{0.62\ kg}\\\\a=0.8\ m/s^2[/tex]
So, the acceleration of the toy is [tex]0.8\ m/s^2[/tex].
In physics, tension is described as the pulling force transmitted axially by the means of a string, a cable, chain, or similar object, or by each end of a rod, truss member, or similar three-dimensional object.
According to the question, the formula we use in this method is F = ma as we have to find the acceleration.
Therefore, the formula for the acceleration is
[tex]a= \frac{F}{m}[/tex]
[tex]a= \frac{0.5}{0.62}[/tex]
Hence, after the calculation, the acceleration is 0.8m/s.
For more information, refer to the link:-
https://brainly.com/question/12550364
