How are the areas of the smaller squares related to the area of the biggest square? Do you notice something?

If a = the side of one small square and b = the side of the other small square and c = the side of the biggest square, then how could you write an equation using a, b, and c with exponents?

This is the Pythagorean Theorem for all Right Triangles. ____________________

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wifilethbridge wifilethbridge · Answer 1 · 2020-10-19T09:14:44+02:00

Answer:

The sum of area of two smaller squares is equal to the area of bigger square

An equation using a, b, and c with exponents is [tex]c^2=a^2+b^2[/tex]

Step-by-step explanation:

Let a be the side of the smallest square , b be the side of other smaller square and c be the side of biggest square

Area of square with side a = [tex]Side^2 = a^2[/tex]

Area of square with side b = [tex]Side^2 = b^2[/tex]

Area of square with side c =[tex]Side^2 = c^2[/tex]

Refer the attached figure

In triangle ABC

[tex]\angle A = 90^{\circ}[/tex]

So, We can use Pythagoras theorem over here

AB = a = Base

AC = b = Perpendicular

BC = c = Hypotenuse

[tex]Hypotenuse^2=Perpendicular^2+Base^2\\c^2=a^2+b^2[/tex]

So, The sum of area of two smaller squares is equal to the area of bigger square

An equation using a, b, and c with exponents is [tex]c^2=a^2+b^2[/tex]