Respuesta :

If it is :

[tex]10 - \frac{ (3x - 1)}{2} = \frac{(6x + 3)}{11} \\ [/tex]

Multiply both sides by 22

[tex](22 \times 10) - 11 \times (3x - 1) = 2 \times (6x + 3) \\ [/tex]

[tex]220 - 33x + 11 = 12x + 6[/tex]

[tex] - 33x + 231 = 12x + 6[/tex]

Plus both sides 33x

[tex]231 = 33x + 12x + 6[/tex]

[tex]231 = 45x + 6[/tex]

Subtract sides minus 6

[tex]231 - 6 = 45x[/tex]

[tex]45x = 225[/tex]

Divided sides by 45

[tex]x = \frac{225}{45} \\ [/tex]

[tex]x = 5[/tex]

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If it is :

[tex] \frac{10 - (3x - 1)}{2} = \frac{6x + 3}{11} \\ [/tex]

Multiply sides by 22

[tex](11 \times 10) - 11 \times (3x - 1) = 2 \times (6x + 3) \\ [/tex]

[tex]110 - 33x + 11 = 12x + 6[/tex]

[tex] - 33x + 121 = 12x + 6[/tex]

Plus sides 33x

[tex]121 = 12x + 33x + 6[/tex]

[tex]121 = 45x + 6[/tex]

Subtract sides minus 6

[tex]121 - 6 = 45x[/tex]

[tex]45x = 115[/tex]

[tex]x = \frac{115}{45} \\ [/tex]

[tex]x = \frac{23}{9} \\ [/tex]

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And we're done.

Thanks for watching buddy good luck.

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