Answer: See the attached image below
Solutions are x = -2 and y = 4
I've arranged the tiles into the correct positions, and wrote in the final result for each x and y.
The basic idea is to divide determinants as the vertical bars indicate (they aren't absolute value bars).
In each denominator is the determinant of the matrix [tex]\begin{bmatrix}2 & 1\\-3 & 4\end{bmatrix}[/tex] which are the coefficients of the left hand side of each original equation given to you.
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The numerators are a slight variation of this matrix. The x determinant will have you replace the first column with 0 & 22 getting [tex]\begin{bmatrix}0 & 1\\22 & 4\end{bmatrix}[/tex] which helps figure out the x solution. The y solution is similar as well, but we replace the y column instead of the x column. So that explains the [tex]\begin{bmatrix}2 & 0\\-3 & 22\end{bmatrix}[/tex]
After you have the proper determinants set up, you just evaluate each determinant using the formula
[tex]\begin{vmatrix}a & b\\ c & d\end{vmatrix} = a*d - b*c[/tex]
and then simplify the results.
