F and g are functions such that
F(x)=3/x2 and g(x)=2x3
A) find f(-4)
B) find fg(1)
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a. The value of f(-4) is [tex]3 \div -8[/tex]
b. The value of fg(1) is [tex]3\div 4[/tex]
Since [tex]F(x)=3\div x\times 2\ and\ g(x)=2\times x\times 3[/tex]
So,
a. The value of f(-4) is
[tex]= 3\div (-4)(2)\\\\= 3\div -8[/tex]
And,
b. The value of fg(1) is
[tex]= 3\div (2(1)^3)(2)\\\\= 3\div (2)(2)\\\\= 3\div 4[/tex]
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