Step-by-step explanation:
Do you mean?
[tex] \frac{ { \tan(x) }^{2} }{ \ { \sin(x) }^{2} } [/tex]
If so:
[tex]3 \sin(x) = 4 \cos(x) \\ \frac{3 \sin(x) }{ \cos(x) } = 4 \\ \frac{ \sin(x) }{ \cos(x) } = \frac{4}{3} \\ \tan(x) = \frac{4}{3} [/tex]
Did the question specify which quadrant? I'm just going to assume that it's the first
(as tangent = opp/adj)
hence
Hypotenuse:
[tex] \sqrt{{3}^{2} + {4}^{2} } = 5[/tex]
[tex] \sin(x) = \frac{4}{5} [/tex]
Finally,
[tex] \frac{ { \tan(x) }^{2} }{ { \sin(x) }^{2} } = \frac{ { \frac{4}{3} }^{2} }{ { \frac{4}{5} }^{2} } \\ = 2 \frac{7}{9} [/tex]
