Answer:
The depth to which the cage will drop for each single rotation of the drum is approximately 18.85 m.
Explanation:
The mine winch drum consists of a drum around around which the haulage rope is attached
Therefore, given that the diameter of the winch drum = 6 m
The length of rope unwound by each rotation = How far the cage will drop for each single rotation of the drum
The length of the rope unwound by each rotation = The rope that goes round the circumference of the winch drum, once
∴ Since the rope that goes round the circumference of the winch drum, once = The circumference of the winch drum, we have;
The length of the rope unwound by each rotation = The circumference of the winch drum = π × The diameter of the winch drum
The length of the rope unwound by each rotation = π × 6 m = 6·π m
The length of rope unwound by each rotation = How far the cage will drop for each single rotation of the drum = 6·π m
How far the cage will drop for each single rotation of the drum = 6·π m ≈ 18.85 m
The depth to which the cage will drop for each single rotation of the drum ≈ 18.85 m.