Answer:
12, 14
Step-by-step explanation:
Let's call the smallest number n.
Let n + 2 = the larger even integer.
Let's write our equation:
"The smaller of two consecutive even integers is five more" would be +5 and "nne half of the greater" can be written as [tex]\frac{1}{2}[/tex](n + 2).
n = 5 + [tex]\frac{1}{2}[/tex](n + 2)
Solvew for n.
n = 5 + [tex]\frac{1}{2}[/tex](n + 2)
Let's multiply each side by 2, to get rid of the fraction, [tex]\frac{1}{2}[/tex].
2 (n) = 2(5 + [tex]\frac{1}{2}[/tex](n + 2))
2n = 2* 5 + 2*([tex]\frac{1}{2}[/tex](n + 2))
2n = 10 + (n + 2)
2n = 10 + n + 2
2n = 10 + 2 + n
2n = 12 + n Subtract n from each side.
2n - n = 12 + n - n
2n - n = 12
n = 12
Let's solve for our other integer:
n + 2 = 12 + 2 = 14
So our 2 consecutive, even integers are
12 and 14
