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An airplane lands with an initial velocity of 70.0 m/s and then decelerates at 1.50 m/s2 for 40.0 s. What is its final velocity?

Respuesta :

Answer:

10 m/s

Explanation:

vi = 70 m/s

a = -1.5 m/s²

t = 40 s

vf = vi + at

= 70 + (-1.5 x 40)

= 10 m/s

Cricetus

The final velocity will be "10 m/s".

Given:

Initial velocity,

  • [tex]v_i = 70 \ m/s[/tex]

Deceleration,

  • [tex]a = -1.50 \ m/s^2[/tex]

Time,

  • [tex]t = 40 \ s[/tex]

As we know,

→ Final velocity, [tex]v_f = v_i+at[/tex]

By substituting the values, we get

                               [tex]= 70+(-1.5\times 40)[/tex]

                               [tex]= 70+(-60)[/tex]

                               [tex]= 70-60[/tex]

                               [tex]= 10 \ m/s[/tex]

Thus the above answer is appropriate.

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