Well, let's see . . .
When n=0, A(n) = 10
Also A(0+1) = A(1) = 4 + 0.6(A0)
= 4 + 0.6(10)
= 4 + 6 = 10
When n=1, A(1+1) = A(2) = 4 + 0.6(A1)
= 4 + 0.6(10)
= 4 + 6 = 10
When n=2, A(2+1) = A(3) = 4 + 0.6(A2)
= 4 + 0.6(10)
= 4 + 6 = 10 .
Amazing ! Whoda thunk it ? !
By my calculations ... which are often bullet-proof and air-tight,
but are just as often worthless and absurd ...
A1, A2, A3, and all other higher terms, are all 10 .