Answer:
[tex]x=0[/tex]
Step-by-step explanation:
we have
[tex]6(x+1)-5x=8+2(x-1)[/tex]
solve for x
[tex]6x+6-5x=8+2x-2[/tex]
Group terms that contain the same variable and move the constants to the other side
[tex]6x-5x-2x=8-2-6[/tex]
[tex]-x=8-8[/tex]
[tex]x=0[/tex]