Suppose a population is carrying a condition controlled by two alleles: R (dominant) and r (recessive). If the frequency of the r allele is 15%, and the frequency of the R allele is 85%, what will be the frequency of the RR genotype, assuming evolution is not occurring?



A. 25.5 percent
B. 72.25 percent
C. 12.75 percent
D. 2.25 percent

Respuesta :

B.) 72.25 percent.

Hopefully this helps! =^ ^= 

Since no evolution is happening we can use the Hardy-Weinberg equation to solve this problem. This equation enables us to calculate the frequency of a genotype from the frequencies of the alleles.

[tex] R^{2} [/tex] the frequency of the dominant homozygote

2Rr the frequency of the heterozygote

[tex] r^{2} [/tex] the frequency of the recessive homozygote

Therefore, the frequency of the RR genotype is R[tex] ^{2} [/tex] = 0,85[tex] ^{2} which is 0,72.