Answer:
choose yourself
Step-by-step explanation:
as I understand it:
[tex](-4x^{-3}y^{-5} )^2\\\\[/tex] correct me if i'm wrong
[tex](-4x^{-3}y^{-5})^2\\\\=(-4)^2(x^{-3})^2(y^{-5})^2\\\\=16(x^{-6})(y^{-10})\\\\=16x^{-6}y^{-10}[/tex]
you can leave it here if you like
[tex]=16(\frac{1}{x^6} )(\frac{1}{y^{10}})\\\\=\frac{16}{x^6y^{10}}[/tex]
