PLEASE HELP ME WITH THIS
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Answer:
C.
Step-by-step explanation:
So we have the equation:
[tex]y=\sqrt{x-3}[/tex]
This is a square root equation.
For square root equations, the radicand(s) must be positive.
Therefore, to find the domain, set the radicand to be greater than or equal to 0:
[tex]x-3\geq 0[/tex]
Solve for x. Add 3 to both sides:
[tex]x\geq 3[/tex]
Therefore, our domain must be greater than or equal to 3.
In set notation, this is:
[tex]\{x:x\geq 3\}[/tex]
Therefore, our answer is C.
All we need to do is solve for the 0 of the function.
Solution:
0 = √x-3
0^2 = x - 3
0 = x - 3
3 = x
The domain is greater than or equal to 3 and this can be written as x ≥ 3 or in other words, Option 3.
Best of Luck!