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I will literally do anything if someone can help me do this test I’ll even PayPal
In independent random samples of 15 men and 15 women, the numbers of minutes spent in front of an electronic device are given by the
back-to-back stemplot below.
Men
1
8
6
6
8
Women
12 35
13 4
14
15 2367
16
17
18
19 035
20
21 4
22. 1
23
24 29
25 7
26
27
28
61
42
90
8761
29
Part A: Describe the shape of each data set. (3 points)
Part B: Josephine analyzed the data and stated that the better measure of center for the women is the meanis Josephine correct? Explain
your reasoning, 3 points)
Part C. Josephine decided there are no outliers in the men's data set. Is she correct? Justify your answer mathematically points) 110
points

I will literally do anything if someone can help me do this test Ill even PayPal In independent random samples of 15 men and 15 women the numbers of minutes spe class=

Respuesta :

Answer:

A. Men: Skewed left

Women: Skewed right

B: Yes, to find the average here it's better and there are no outliers

C: There are no outliers

Explanation:

C: There are no outliers

1,8,6,6,8,6,1,4,2,9,0,8,7,6,1

(n+1)/2=(15+1)/2=8      median=6

pos(Q1​)=(n+1)10025​=(15+1)10025​=4

Q1​=2

pos(Q3​)=(n+1)10075​=(15+1)10075​=12

Q3​=8

IQR=Q3​−Q1​=8−2=6

Lower=Q1​−1.5 x IQR=2−1.5 x 6=−7Upper = Q3+ 1.5 x IQR = 8 + 1.5 x 6 = 17     Upper=Q3​+ 1.5 x IQR=8+1.5 x 6=17

all values within x < −7 and X > 17

A. Men: Skewed left

Women: Skewed right

B: Yes, Joseph is correct. To find the average here it's better and there are no outliers

C: Yes, she is correct. There are no outliers in the men's data set.

Explanation:

C: There are no outliers

What is mean?

The mean of observations is equal to the ratio of sum of all the individual observations and the number of observations.

1,8,6,6,8,6,1,4,2,9,0,8,7,6,1

Median is the mid term of the data when arranged in increasing order = (n+1)/2=(15+1)/2=8    

Median=6

pos(Q1​)=(n+1)10025​

pos(Q1​)=(15+1)10025​=4

Q1​=2

pos(Q3​)=(n+1)10075​

pos(Q3​)=(15+1)10075​=12

Q3​=8

IQR=Q3​−Q1​=8−2=6

Lower=Q1​−1.5 x IQR

Lower=2−1.5 x 6

Lower=−7

Upper = Q3+ 1.5 x IQR

Upper = 8 + 1.5 x 6

Upper = 17    

So, all the values lie within 17< x < −7

Learn more about mean.

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